Make error_traceback never trigger a Lua error
It is called from both Lua and Rust, and any error would hide the error it's trying to generate a traceback for.
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parent
b07557c1c7
commit
0450c9b597
19
src/util.rs
19
src/util.rs
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@ -312,14 +312,21 @@ where
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// traceback, and if it is a WrappedPanic, does not modify it.
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#[cfg_attr(unwind, unwind)]
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pub unsafe extern "C" fn error_traceback(state: *mut ffi::lua_State) -> c_int {
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ffi::luaL_checkstack(state, 2, ptr::null());
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if is_wrapped_error(state, 1) {
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if ffi::lua_checkstack(state, 2) == 0 {
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// If we don't have enough stack space to even check the error type, do nothing
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} else if is_wrapped_error(state, 1) {
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let traceback = if ffi::lua_checkstack(state, 11) != 0 {
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gc_guard(state, || {
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ffi::luaL_traceback(state, state, ptr::null(), 0);
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});
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let traceback = CStr::from_ptr(ffi::lua_tostring(state, -1))
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.to_string_lossy()
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.into_owned();
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ffi::lua_pop(state, 1);
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traceback
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} else {
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"not enough stack space for traceback".to_owned()
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};
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let error = pop_wrapped_error(state).unwrap();
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push_wrapped_error(
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@ -330,14 +337,18 @@ pub unsafe extern "C" fn error_traceback(state: *mut ffi::lua_State) -> c_int {
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},
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);
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} else if !is_wrapped_panic(state, 1) {
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if ffi::lua_checkstack(state, 11) != 0 {
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gc_guard(state, || {
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let s = ffi::lua_tostring(state, 1);
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let s = if s.is_null() {
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cstr!("<unprintable Rust panic>")
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cstr!("<unprintable lua error>")
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} else {
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s
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};
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ffi::luaL_traceback(state, state, s, 0);
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ffi::lua_remove(state, -2);
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});
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}
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}
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1
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}
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